Line slope calculator 4x+5y=56
Straight line given by points A[4; 8] and B[9; 4]
Calculation:
Slope: m = -0.8Slope-intercept form of line: y = -0.8x+11.2
Canonical form of the line equation: 4x+5y-56 = 0
Parametric form of the line equation:
x = 5t+4
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -38°39'35″ = -0.6747 rad
X intercept: x0 = 14
Y intercept: y0 = q = 11.2
Distance line from the origin: d0 = 8.7457
The length of the segment AB: |AB| = 6.4031
Vector: AB = (5; -4)
Normal vector: n = (4; 5)
Midpoint of the segment AB: M = [6.5; 6]
Perpendicular Bisector equation: 5x-4y-8.5 = 0
Vector OA = (4; 8) ; |OA| = 8.9443
Vector OB = (9; 4) ; |OB| = 9.8489
Scalar product OA .OB = 68
Angle ∠ AOB = 39°28'21″ = 0.6889 rad