Line slope calculator 3x-5y=15
Straight line given by points A[5; 0] and B[10; 3]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x-3
Canonical form of the line equation: 3x-5y-15 = 0
Parametric form of the line equation:
x = 5t+5
y = 3t ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = 5
Y intercept: y0 = q = -3
Distance line from the origin: d0 = 2.5725
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [7.5; 1.5]
Perpendicular Bisector equation: 5x+3y-42 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 50
Angle ∠ AOB = 16°41'57″ = 0.2915 rad