Line slope calculator 3x-5y=15


Enter coordinates of two different points:

Straight line given by points A[5; 0] and B[10; 3]

Calculation:

Slope-intercept form of line: y = 0.6x-3

Canonical form of the line equation: 3x-5y-15 = 0

Parametric form of the line equation:
x = 5t+5
y = 3t      ; t ∈ R

Slope: m = 0.6

Slope angle of line: φ = 30°57'50″ = 0.5404 rad

X intercept: x0 = 5

Y intercept: y0 = q = -3

Distance line from the origin: d0 = 2.5725

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; 3)

Normal vector: n = (3; -5)

Midpoint of the segment AB: M = [7.5; 1.5]

Perpendicular Bisector equation: 5x+3y-42 = 0


Vector OA = (5; 0) ;   |OA| = 5
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 50
Angle ∠ AOB = 16°41'57″ = 0.2915 rad