Line slope calculator 8x-5y=40


Enter coordinates of two different points:

Straight line given by points A[5; 0] and B[10; 8]

Calculation:

Slope-intercept form of line: y = 1.6x-8

Canonical form of the line equation: 8x-5y-40 = 0

Parametric form of the line equation:
x = 5t+5
y = 8t      ; t ∈ R

Slope: m = 1.6

Slope angle of line: φ = 57°59'41″ = 1.0122 rad

X intercept: x0 = 5

Y intercept: y0 = q = -8

Distance line from the origin: d0 = 4.24

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; 8)

Normal vector: n = (8; -5)

Midpoint of the segment AB: M = [7.5; 4]

Perpendicular Bisector equation: 5x+8y-69.5 = 0


Vector OA = (5; 0) ;   |OA| = 5
Vector OB = (10; 8) ;   |OB| = 12.8062
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad