Line slope calculator 8x-5y=40
Straight line given by points A[5; 0] and B[10; 8]
Calculation:
Slope: m = 1.6Slope-intercept form of line: y = 1.6x-8
Canonical form of the line equation: 8x-5y-40 = 0
Parametric form of the line equation:
x = 5t+5
y = 8t ; t ∈ R
Slope angle of line: φ = 57°59'41″ = 1.0122 rad
X intercept: x0 = 5
Y intercept: y0 = q = -8
Distance line from the origin: d0 = 4.24
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; 8)
Normal vector: n = (8; -5)
Midpoint of the segment AB: M = [7.5; 4]
Perpendicular Bisector equation: 5x+8y-69.5 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (10; 8) ; |OB| = 12.8062
Scalar product OA .OB = 50
Angle ∠ AOB = 38°39'35″ = 0.6747 rad