Line slope calculator x-3y=5
Straight line given by points A[5; 0] and B[8; 1]
Calculation:
Slope: m = 0.3333Slope-intercept form of line: y = 0.3333x-1.6667
Canonical form of the line equation: x-3y-5 = 0
Parametric form of the line equation:
x = 3t+5
y = t ; t ∈ R
Slope angle of line: φ = 18°26'6″ = 0.3218 rad
X intercept: x0 = 5
Y intercept: y0 = q = -1.6667
Distance line from the origin: d0 = 1.5811
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; 1)
Normal vector: n = (1; -3)
Midpoint of the segment AB: M = [6.5; 0.5]
Perpendicular Bisector equation: 3x+y-20 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (8; 1) ; |OB| = 8.0623
Scalar product OA .OB = 40
Angle ∠ AOB = 7°7'30″ = 0.1244 rad