Line slope calculator 2x-3y=10
Straight line given by points A[5; 0] and B[8; 2]
Calculation:
Slope: m = 0.6667Slope-intercept form of line: y = 0.6667x-3.3333
Canonical form of the line equation: 2x-3y-10 = 0
Parametric form of the line equation:
x = 3t+5
y = 2t ; t ∈ R
Slope angle of line: φ = 33°41'24″ = 0.588 rad
X intercept: x0 = 5
Y intercept: y0 = q = -3.3333
Distance line from the origin: d0 = 2.7735
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; 2)
Normal vector: n = (2; -3)
Midpoint of the segment AB: M = [6.5; 1]
Perpendicular Bisector equation: 3x+2y-21.5 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (8; 2) ; |OB| = 8.2462
Scalar product OA .OB = 40
Angle ∠ AOB = 14°2'10″ = 0.245 rad