Line slope calculator 5x-3y=25
Straight line given by points A[5; 0] and B[8; 5]
Calculation:
Slope: m = 1.6667Slope-intercept form of line: y = 1.6667x-8.3333
Canonical form of the line equation: 5x-3y-25 = 0
Parametric form of the line equation:
x = 3t+5
y = 5t ; t ∈ R
Slope angle of line: φ = 59°2'10″ = 1.0304 rad
X intercept: x0 = 5
Y intercept: y0 = q = -8.3333
Distance line from the origin: d0 = 4.2875
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; 5)
Normal vector: n = (5; -3)
Midpoint of the segment AB: M = [6.5; 2.5]
Perpendicular Bisector equation: 3x+5y-32 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 40
Angle ∠ AOB = 32°19″ = 0.5586 rad