Line slope calculator 8x-3y=40


Enter coordinates of two different points:

Straight line given by points A[5; 0] and B[8; 8]

Calculation:

Slope-intercept form of line: y = 2.6667x-13.3333

Canonical form of the line equation: 8x-3y-40 = 0

Parametric form of the line equation:
x = 3t+5
y = 8t      ; t ∈ R

Slope: m = 2.6667

Slope angle of line: φ = 69°26'38″ = 1.212 rad

X intercept: x0 = 5

Y intercept: y0 = q = -13.3333

Distance line from the origin: d0 = 4.6816

The length of the segment AB: |AB| = 8.544

Vector: AB = (3; 8)

Normal vector: n = (8; -3)

Midpoint of the segment AB: M = [6.5; 4]

Perpendicular Bisector equation: 3x+8y-51.5 = 0


Vector OA = (5; 0) ;   |OA| = 5
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 40
Angle ∠ AOB = 45° = 0.7854 rad