Line slope calculator x-4y=5
Straight line given by points A[5; 0] and B[9; 1]
Calculation:
Slope: m = 0.25Slope-intercept form of line: y = 0.25x-1.25
Canonical form of the line equation: x-4y-5 = 0
Parametric form of the line equation:
x = 4t+5
y = t ; t ∈ R
Slope angle of line: φ = 14°2'10″ = 0.245 rad
X intercept: x0 = 5
Y intercept: y0 = q = -1.25
Distance line from the origin: d0 = 1.2127
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; 1)
Normal vector: n = (1; -4)
Midpoint of the segment AB: M = [7; 0.5]
Perpendicular Bisector equation: 4x+y-28.5 = 0
Vector OA = (5; 0) ; |OA| = 5
Vector OB = (9; 1) ; |OB| = 9.0554
Scalar product OA .OB = 45
Angle ∠ AOB = 6°20'25″ = 0.1107 rad