Line slope calculator 3x-5y=10
Straight line given by points A[5; 1] and B[10; 4]
Calculation:
Slope: m = 0.6Slope-intercept form of line: y = 0.6x-2
Canonical form of the line equation: 3x-5y-10 = 0
Parametric form of the line equation:
x = 5t+5
y = 3t+1 ; t ∈ R
Slope angle of line: φ = 30°57'50″ = 0.5404 rad
X intercept: x0 = 3.3333
Y intercept: y0 = q = -2
Distance line from the origin: d0 = 1.715
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; 3)
Normal vector: n = (3; -5)
Midpoint of the segment AB: M = [7.5; 2.5]
Perpendicular Bisector equation: 5x+3y-45 = 0
Vector OA = (5; 1) ; |OA| = 5.099
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 54
Angle ∠ AOB = 10°29'29″ = 0.1831 rad