Line slope calculator 9x+5y=95
Straight line given by points A[5; 10] and B[10; 1]
Calculation:
Slope: m = -1.8Slope-intercept form of line: y = -1.8x+19
Canonical form of the line equation: 9x+5y-95 = 0
Parametric form of the line equation:
x = 5t+5
y = -9t+10 ; t ∈ R
Slope angle of line: φ = -60°56'43″ = -1.0637 rad
X intercept: x0 = 10.5556
Y intercept: y0 = q = 19
Distance line from the origin: d0 = 9.2272
The length of the segment AB: |AB| = 10.2956
Vector: AB = (5; -9)
Normal vector: n = (9; 5)
Midpoint of the segment AB: M = [7.5; 5.5]
Perpendicular Bisector equation: 5x-9y+12 = 0
Vector OA = (5; 10) ; |OA| = 11.1803
Vector OB = (10; 1) ; |OB| = 10.0499
Scalar product OA .OB = 60
Angle ∠ AOB = 57°43'28″ = 1.0075 rad