Line slope calculator 9x+5y=95


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[10; 1]

Calculation:

Slope-intercept form of line: y = -1.8x+19

Canonical form of the line equation: 9x+5y-95 = 0

Parametric form of the line equation:
x = 5t+5
y = -9t+10      ; t ∈ R

Slope: m = -1.8

Slope angle of line: φ = -60°56'43″ = -1.0637 rad

X intercept: x0 = 10.5556

Y intercept: y0 = q = 19

Distance line from the origin: d0 = 9.2272

The length of the segment AB: |AB| = 10.2956

Vector: AB = (5; -9)

Normal vector: n = (9; 5)

Midpoint of the segment AB: M = [7.5; 5.5]

Perpendicular Bisector equation: 5x-9y+12 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (10; 1) ;   |OB| = 10.0499
Scalar product OA .OB = 60
Angle ∠ AOB = 57°43'28″ = 1.0075 rad