Line slope calculator 8x+5y=90


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[10; 2]

Calculation:

Slope-intercept form of line: y = -1.6x+18

Canonical form of the line equation: 8x+5y-90 = 0

Parametric form of the line equation:
x = 5t+5
y = -8t+10      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 11.25

Y intercept: y0 = q = 18

Distance line from the origin: d0 = 9.54

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [7.5; 6]

Perpendicular Bisector equation: 5x-8y+10.5 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (10; 2) ;   |OB| = 10.198
Scalar product OA .OB = 70
Angle ∠ AOB = 52°7'30″ = 0.9098 rad