Line slope calculator 6x+5y=80
Straight line given by points A[5; 10] and B[10; 4]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+16
Canonical form of the line equation: 6x+5y-80 = 0
Parametric form of the line equation:
x = 5t+5
y = -6t+10 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 13.3333
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 10.243
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [7.5; 7]
Perpendicular Bisector equation: 5x-6y+4.5 = 0
Vector OA = (5; 10) ; |OA| = 11.1803
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 90
Angle ∠ AOB = 41°38'1″ = 0.7266 rad