Line slope calculator 6x+5y=80


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[10; 4]

Calculation:

Slope-intercept form of line: y = -1.2x+16

Canonical form of the line equation: 6x+5y-80 = 0

Parametric form of the line equation:
x = 5t+5
y = -6t+10      ; t ∈ R

Slope: m = -1.2

Slope angle of line: φ = -50°11'40″ = -0.8761 rad

X intercept: x0 = 13.3333

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 10.243

The length of the segment AB: |AB| = 7.8102

Vector: AB = (5; -6)

Normal vector: n = (6; 5)

Midpoint of the segment AB: M = [7.5; 7]

Perpendicular Bisector equation: 5x-6y+4.5 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (10; 4) ;   |OB| = 10.7703
Scalar product OA .OB = 90
Angle ∠ AOB = 41°38'1″ = 0.7266 rad