Line slope calculator 9x+y=55


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -9x+55

Canonical form of the line equation: 9x+y-55 = 0

Parametric form of the line equation:
x = t+5
y = -9t+10      ; t ∈ R

Slope: m = -9

Slope angle of line: φ = -83°39'35″ = -1.4601 rad

X intercept: x0 = 6.1111

Y intercept: y0 = q = 55

Distance line from the origin: d0 = 6.0737

The length of the segment AB: |AB| = 9.0554

Vector: AB = (1; -9)

Normal vector: n = (9; 1)

Midpoint of the segment AB: M = [5.5; 5.5]

Perpendicular Bisector equation: x-9y+44 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 40
Angle ∠ AOB = 53°58'21″ = 0.942 rad