Line slope calculator 8x+y=50
Straight line given by points A[5; 10] and B[6; 2]
Calculation:
Slope: m = -8Slope-intercept form of line: y = -8x+50
Canonical form of the line equation: 8x+y-50 = 0
Parametric form of the line equation:
x = t+5
y = -8t+10 ; t ∈ R
Slope angle of line: φ = -82°52'30″ = -1.4464 rad
X intercept: x0 = 6.25
Y intercept: y0 = q = 50
Distance line from the origin: d0 = 6.2017
The length of the segment AB: |AB| = 8.0623
Vector: AB = (1; -8)
Normal vector: n = (8; 1)
Midpoint of the segment AB: M = [5.5; 6]
Perpendicular Bisector equation: x-8y+42.5 = 0
Vector OA = (5; 10) ; |OA| = 11.1803
Vector OB = (6; 2) ; |OB| = 6.3246
Scalar product OA .OB = 50
Angle ∠ AOB = 45° = 0.7854 rad