Line slope calculator 6x+y=40


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[6; 4]

Calculation:

Slope-intercept form of line: y = -6x+40

Canonical form of the line equation: 6x+y-40 = 0

Parametric form of the line equation:
x = t+5
y = -6t+10      ; t ∈ R

Slope: m = -6

Slope angle of line: φ = -80°32'16″ = -1.4056 rad

X intercept: x0 = 6.6667

Y intercept: y0 = q = 40

Distance line from the origin: d0 = 6.576

The length of the segment AB: |AB| = 6.0828

Vector: AB = (1; -6)

Normal vector: n = (6; 1)

Midpoint of the segment AB: M = [5.5; 7]

Perpendicular Bisector equation: x-6y+36.5 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (6; 4) ;   |OB| = 7.2111
Scalar product OA .OB = 70
Angle ∠ AOB = 29°44'42″ = 0.5191 rad