Line slope calculator 5x+y=35
Straight line given by points A[5; 10] and B[6; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+35
Canonical form of the line equation: 5x+y-35 = 0
Parametric form of the line equation:
x = t+5
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 7
Y intercept: y0 = q = 35
Distance line from the origin: d0 = 6.8641
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [5.5; 7.5]
Perpendicular Bisector equation: x-5y+32 = 0
Vector OA = (5; 10) ; |OA| = 11.1803
Vector OB = (6; 5) ; |OB| = 7.8102
Scalar product OA .OB = 80
Angle ∠ AOB = 23°37'46″ = 0.4124 rad