Line slope calculator x+y=15


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[7; 8]

Calculation:

Slope-intercept form of line: y = -x+15

Canonical form of the line equation: x+y-15 = 0

Parametric form of the line equation:
x = t+5
y = -t+10      ; t ∈ R

Slope: m = -1

Slope angle of line: φ = -45° = -0.7854 rad

X intercept: x0 = 15

Y intercept: y0 = q = 15

Distance line from the origin: d0 = 10.6066

The length of the segment AB: |AB| = 2.8284

Vector: AB = (2; -2)

Normal vector: n = (1; 1)

Midpoint of the segment AB: M = [6; 9]

Perpendicular Bisector equation: 2x-2y+6 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (7; 8) ;   |OB| = 10.6301
Scalar product OA .OB = 115
Angle ∠ AOB = 14°37'15″ = 0.2552 rad