Line slope calculator 10x+3y=80
Straight line given by points A[5; 10] and B[8; 0]
Calculation:
Slope: m = -3.3333Slope-intercept form of line: y = -3.3333x+26.6667
Canonical form of the line equation: 10x+3y-80 = 0
Parametric form of the line equation:
x = 3t+5
y = -10t+10 ; t ∈ R
Slope angle of line: φ = -73°18'3″ = -1.2793 rad
X intercept: x0 = 8
Y intercept: y0 = q = 26.6667
Distance line from the origin: d0 = 7.6626
The length of the segment AB: |AB| = 10.4403
Vector: AB = (3; -10)
Normal vector: n = (10; 3)
Midpoint of the segment AB: M = [6.5; 5]
Perpendicular Bisector equation: 3x-10y+30.5 = 0
Vector OA = (5; 10) ; |OA| = 11.1803
Vector OB = (8; 0) ; |OB| = 8
Scalar product OA .OB = 40
Angle ∠ AOB = 63°26'6″ = 1.1071 rad