Line slope calculator 5x+3y=55


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[8; 5]

Calculation:

Slope-intercept form of line: y = -1.6667x+18.3333

Canonical form of the line equation: 5x+3y-55 = 0

Parametric form of the line equation:
x = 3t+5
y = -5t+10      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 11

Y intercept: y0 = q = 18.3333

Distance line from the origin: d0 = 9.4324

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [6.5; 7.5]

Perpendicular Bisector equation: 3x-5y+18 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (8; 5) ;   |OB| = 9.434
Scalar product OA .OB = 90
Angle ∠ AOB = 31°25'46″ = 0.5485 rad