Line slope calculator 4x+3y=50


Enter coordinates of two different points:

Straight line given by points A[5; 10] and B[8; 6]

Calculation:

Slope-intercept form of line: y = -1.3333x+16.6667

Canonical form of the line equation: 4x+3y-50 = 0

Parametric form of the line equation:
x = 3t+5
y = -4t+10      ; t ∈ R

Slope: m = -1.3333

Slope angle of line: φ = -53°7'48″ = -0.9273 rad

X intercept: x0 = 12.5

Y intercept: y0 = q = 16.6667

Distance line from the origin: d0 = 10

The length of the segment AB: |AB| = 5

Vector: AB = (3; -4)

Normal vector: n = (4; 3)

Midpoint of the segment AB: M = [6.5; 8]

Perpendicular Bisector equation: 3x-4y+12.5 = 0


Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (8; 6) ;   |OB| = 10
Scalar product OA .OB = 100
Angle ∠ AOB = 26°33'54″ = 0.4636 rad