Line slope calculator 2x+3y=40


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[5; 10] and B[8; 8]

Calculation:

Slope: m = -0.6667

Slope-intercept form of line: y = -0.6667x+13.3333

Canonical form of the line equation: 2x+3y-40 = 0

Parametric form of the line equation:
x = 3t+5
y = -2t+10      ; t ∈ R

Slope angle of line: φ = -33°41'24″ = -0.588 rad

X intercept: x0 = 20

Y intercept: y0 = q = 13.3333

Distance line from the origin: d0 = 11.094

The length of the segment AB: |AB| = 3.6056

Vector: AB = (3; -2)

Normal vector: n = (2; 3)

Midpoint of the segment AB: M = [6.5; 9]

Perpendicular Bisector equation: 3x-2y-1.5 = 0

Vector OA = (5; 10) ;   |OA| = 11.1803
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 120
Angle ∠ AOB = 18°26'6″ = 0.3218 rad