Line slope calculator 5x-3y=16


Enter coordinates of two different points:

Straight line given by points A[5; 3] and B[8; 8]

Calculation:

Slope-intercept form of line: y = 1.6667x-5.3333

Canonical form of the line equation: 5x-3y-16 = 0

Parametric form of the line equation:
x = 3t+5
y = 5t+3      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = 3.2

Y intercept: y0 = q = -5.3333

Distance line from the origin: d0 = 2.744

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [6.5; 5.5]

Perpendicular Bisector equation: 3x+5y-47 = 0


Vector OA = (5; 3) ;   |OA| = 5.831
Vector OB = (8; 8) ;   |OB| = 11.3137
Scalar product OA .OB = 64
Angle ∠ AOB = 14°2'10″ = 0.245 rad