Line slope calculator 5x-4y=13


Enter coordinates of two different points:

Straight line given by points A[5; 3] and B[9; 8]

Calculation:

Slope-intercept form of line: y = 1.25x-3.25

Canonical form of the line equation: 5x-4y-13 = 0

Parametric form of the line equation:
x = 4t+5
y = 5t+3      ; t ∈ R

Slope: m = 1.25

Slope angle of line: φ = 51°20'25″ = 0.8961 rad

X intercept: x0 = 2.6

Y intercept: y0 = q = -3.25

Distance line from the origin: d0 = 2.0303

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; 5)

Normal vector: n = (5; -4)

Midpoint of the segment AB: M = [7; 5.5]

Perpendicular Bisector equation: 4x+5y-55.5 = 0


Vector OA = (5; 3) ;   |OA| = 5.831
Vector OB = (9; 8) ;   |OB| = 12.0416
Scalar product OA .OB = 69
Angle ∠ AOB = 10°40'11″ = 0.1862 rad