Line slope calculator 3x+5y=35


Enter coordinates of two different points:

Straight line given by points A[5; 4] and B[10; 1]

Calculation:

Slope-intercept form of line: y = -0.6x+7

Canonical form of the line equation: 3x+5y-35 = 0

Parametric form of the line equation:
x = 5t+5
y = -3t+4      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 11.6667

Y intercept: y0 = q = 7

Distance line from the origin: d0 = 6.0025

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [7.5; 2.5]

Perpendicular Bisector equation: 5x-3y-30 = 0


Vector OA = (5; 4) ;   |OA| = 6.4031
Vector OB = (10; 1) ;   |OB| = 10.0499
Scalar product OA .OB = 54
Angle ∠ AOB = 32°56'57″ = 0.5751 rad