Line slope calculator 2x+5y=35
Straight line given by points A[5; 5] and B[10; 3]
Calculation:
Slope: m = -0.4Slope-intercept form of line: y = -0.4x+7
Canonical form of the line equation: 2x+5y-35 = 0
Parametric form of the line equation:
x = 5t+5
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -21°48'5″ = -0.3805 rad
X intercept: x0 = 17.5
Y intercept: y0 = q = 7
Distance line from the origin: d0 = 6.4993
The length of the segment AB: |AB| = 5.3852
Vector: AB = (5; -2)
Normal vector: n = (2; 5)
Midpoint of the segment AB: M = [7.5; 4]
Perpendicular Bisector equation: 5x-2y-29.5 = 0
Vector OA = (5; 5) ; |OA| = 7.0711
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 65
Angle ∠ AOB = 28°18'3″ = 0.4939 rad