Line slope calculator 4x+y=25


Enter coordinates of two different points:

Straight line given by points A[5; 5] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -4x+25

Canonical form of the line equation: 4x+y-25 = 0

Parametric form of the line equation:
x = t+5
y = -4t+5      ; t ∈ R

Slope: m = -4

Slope angle of line: φ = -75°57'50″ = -1.3258 rad

X intercept: x0 = 6.25

Y intercept: y0 = q = 25

Distance line from the origin: d0 = 6.0634

The length of the segment AB: |AB| = 4.1231

Vector: AB = (1; -4)

Normal vector: n = (4; 1)

Midpoint of the segment AB: M = [5.5; 3]

Perpendicular Bisector equation: x-4y+6.5 = 0


Vector OA = (5; 5) ;   |OA| = 7.0711
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 35
Angle ∠ AOB = 35°32'16″ = 0.6202 rad