Line slope calculator 4x+y=25
Straight line given by points A[5; 5] and B[6; 1]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+25
Canonical form of the line equation: 4x+y-25 = 0
Parametric form of the line equation:
x = t+5
y = -4t+5 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 6.25
Y intercept: y0 = q = 25
Distance line from the origin: d0 = 6.0634
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [5.5; 3]
Perpendicular Bisector equation: x-4y+6.5 = 0
Vector OA = (5; 5) ; |OA| = 7.0711
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 35
Angle ∠ AOB = 35°32'16″ = 0.6202 rad