Line slope calculator 2x+y=15
Straight line given by points A[5; 5] and B[6; 3]
Calculation:
Slope: m = -2Slope-intercept form of line: y = -2x+15
Canonical form of the line equation: 2x+y-15 = 0
Parametric form of the line equation:
x = t+5
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -63°26'6″ = -1.1071 rad
X intercept: x0 = 7.5
Y intercept: y0 = q = 15
Distance line from the origin: d0 = 6.7082
The length of the segment AB: |AB| = 2.2361
Vector: AB = (1; -2)
Normal vector: n = (2; 1)
Midpoint of the segment AB: M = [5.5; 4]
Perpendicular Bisector equation: x-2y+2.5 = 0
Vector OA = (5; 5) ; |OA| = 7.0711
Vector OB = (6; 3) ; |OB| = 6.7082
Scalar product OA .OB = 45
Angle ∠ AOB = 18°26'6″ = 0.3218 rad