Line slope calculator 2x+3y=25
Straight line given by points A[5; 5] and B[8; 3]
Calculation:
Slope: m = -0.6667Slope-intercept form of line: y = -0.6667x+8.3333
Canonical form of the line equation: 2x+3y-25 = 0
Parametric form of the line equation:
x = 3t+5
y = -2t+5 ; t ∈ R
Slope angle of line: φ = -33°41'24″ = -0.588 rad
X intercept: x0 = 12.5
Y intercept: y0 = q = 8.3333
Distance line from the origin: d0 = 6.9338
The length of the segment AB: |AB| = 3.6056
Vector: AB = (3; -2)
Normal vector: n = (2; 3)
Midpoint of the segment AB: M = [6.5; 4]
Perpendicular Bisector equation: 3x-2y-11.5 = 0
Vector OA = (5; 5) ; |OA| = 7.0711
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 55
Angle ∠ AOB = 24°26'38″ = 0.4266 rad