Line slope calculator 6x+5y=60
Straight line given by points A[5; 6] and B[10; 0]
Calculation:
Slope: m = -1.2Slope-intercept form of line: y = -1.2x+12
Canonical form of the line equation: 6x+5y-60 = 0
Parametric form of the line equation:
x = 5t+5
y = -6t+6 ; t ∈ R
Slope angle of line: φ = -50°11'40″ = -0.8761 rad
X intercept: x0 = 10
Y intercept: y0 = q = 12
Distance line from the origin: d0 = 7.6822
The length of the segment AB: |AB| = 7.8102
Vector: AB = (5; -6)
Normal vector: n = (6; 5)
Midpoint of the segment AB: M = [7.5; 3]
Perpendicular Bisector equation: 5x-6y-19.5 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 50
Angle ∠ AOB = 50°11'40″ = 0.8761 rad