Line slope calculator 3x+5y=45
Straight line given by points A[5; 6] and B[10; 3]
Calculation:
Slope: m = -0.6Slope-intercept form of line: y = -0.6x+9
Canonical form of the line equation: 3x+5y-45 = 0
Parametric form of the line equation:
x = 5t+5
y = -3t+6 ; t ∈ R
Slope angle of line: φ = -30°57'50″ = -0.5404 rad
X intercept: x0 = 15
Y intercept: y0 = q = 9
Distance line from the origin: d0 = 7.7174
The length of the segment AB: |AB| = 5.831
Vector: AB = (5; -3)
Normal vector: n = (3; 5)
Midpoint of the segment AB: M = [7.5; 4.5]
Perpendicular Bisector equation: 5x-3y-24 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 68
Angle ∠ AOB = 33°29'43″ = 0.5846 rad