Line slope calculator 5x+y=31


Enter coordinates of two different points:

Straight line given by points A[5; 6] and B[6; 1]

Calculation:

Slope-intercept form of line: y = -5x+31

Canonical form of the line equation: 5x+y-31 = 0

Parametric form of the line equation:
x = t+5
y = -5t+6      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 6.2

Y intercept: y0 = q = 31

Distance line from the origin: d0 = 6.0796

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [5.5; 3.5]

Perpendicular Bisector equation: x-5y+12 = 0


Vector OA = (5; 6) ;   |OA| = 7.8102
Vector OB = (6; 1) ;   |OB| = 6.0828
Scalar product OA .OB = 36
Angle ∠ AOB = 40°43'56″ = 0.7109 rad