Line slope calculator 5x+y=31
Straight line given by points A[5; 6] and B[6; 1]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+31
Canonical form of the line equation: 5x+y-31 = 0
Parametric form of the line equation:
x = t+5
y = -5t+6 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 6.2
Y intercept: y0 = q = 31
Distance line from the origin: d0 = 6.0796
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [5.5; 3.5]
Perpendicular Bisector equation: x-5y+12 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (6; 1) ; |OB| = 6.0828
Scalar product OA .OB = 36
Angle ∠ AOB = 40°43'56″ = 0.7109 rad