Line slope calculator 5x+3y=43


Enter coordinates of two different points:

Straight line given by points A[5; 6] and B[8; 1]

Calculation:

Slope-intercept form of line: y = -1.6667x+14.3333

Canonical form of the line equation: 5x+3y-43 = 0

Parametric form of the line equation:
x = 3t+5
y = -5t+6      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 8.6

Y intercept: y0 = q = 14.3333

Distance line from the origin: d0 = 7.3744

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [6.5; 3.5]

Perpendicular Bisector equation: 3x-5y-2 = 0


Vector OA = (5; 6) ;   |OA| = 7.8102
Vector OB = (8; 1) ;   |OB| = 8.0623
Scalar product OA .OB = 46
Angle ∠ AOB = 43°4'10″ = 0.7517 rad