Line slope calculator x+3y=23
Straight line given by points A[5; 6] and B[8; 5]
Calculation:
Slope: m = -0.3333Slope-intercept form of line: y = -0.3333x+7.6667
Canonical form of the line equation: x+3y-23 = 0
Parametric form of the line equation:
x = 3t+5
y = -t+6 ; t ∈ R
Slope angle of line: φ = -18°26'6″ = -0.3218 rad
X intercept: x0 = 23
Y intercept: y0 = q = 7.6667
Distance line from the origin: d0 = 7.2732
The length of the segment AB: |AB| = 3.1623
Vector: AB = (3; -1)
Normal vector: n = (1; 3)
Midpoint of the segment AB: M = [6.5; 5.5]
Perpendicular Bisector equation: 3x-y-14 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (8; 5) ; |OB| = 9.434
Scalar product OA .OB = 70
Angle ∠ AOB = 18°11'21″ = 0.3175 rad