Line slope calculator 5x+4y=49


Enter coordinates of two different points:

Straight line given by points A[5; 6] and B[9; 1]

Calculation:

Slope-intercept form of line: y = -1.25x+12.25

Canonical form of the line equation: 5x+4y-49 = 0

Parametric form of the line equation:
x = 4t+5
y = -5t+6      ; t ∈ R

Slope: m = -1.25

Slope angle of line: φ = -51°20'25″ = -0.8961 rad

X intercept: x0 = 9.8

Y intercept: y0 = q = 12.25

Distance line from the origin: d0 = 7.6525

The length of the segment AB: |AB| = 6.4031

Vector: AB = (4; -5)

Normal vector: n = (5; 4)

Midpoint of the segment AB: M = [7; 3.5]

Perpendicular Bisector equation: 4x-5y-10.5 = 0


Vector OA = (5; 6) ;   |OA| = 7.8102
Vector OB = (9; 1) ;   |OB| = 9.0554
Scalar product OA .OB = 51
Angle ∠ AOB = 43°51'15″ = 0.7654 rad