Line slope calculator 3x+4y=39


Enter the coordinates of two different points:
Line slope diagram

Straight line given by points A[5; 6] and B[9; 3]

Calculation:

Slope: m = -0.75

Slope-intercept form of line: y = -0.75x+9.75

Canonical form of the line equation: 3x+4y-39 = 0

Parametric form of the line equation:
x = 4t+5
y = -3t+6      ; t ∈ R

Slope angle of line: φ = -36°52'12″ = -0.6435 rad

X intercept: x0 = 13

Y intercept: y0 = q = 9.75

Distance line from the origin: d0 = 7.8

The length of the segment AB: |AB| = 5

Vector: AB = (4; -3)

Normal vector: n = (3; 4)

Midpoint of the segment AB: M = [7; 4.5]

Perpendicular Bisector equation: 4x-3y-14.5 = 0

Vector OA = (5; 6) ;   |OA| = 7.8102
Vector OB = (9; 3) ;   |OB| = 9.4868
Scalar product OA .OB = 63
Angle ∠ AOB = 31°45'34″ = 0.5543 rad