Line slope calculator x+4y=29
Straight line given by points A[5; 6] and B[9; 5]
Calculation:
Slope: m = -0.25Slope-intercept form of line: y = -0.25x+7.25
Canonical form of the line equation: x+4y-29 = 0
Parametric form of the line equation:
x = 4t+5
y = -t+6 ; t ∈ R
Slope angle of line: φ = -14°2'10″ = -0.245 rad
X intercept: x0 = 29
Y intercept: y0 = q = 7.25
Distance line from the origin: d0 = 7.0335
The length of the segment AB: |AB| = 4.1231
Vector: AB = (4; -1)
Normal vector: n = (1; 4)
Midpoint of the segment AB: M = [7; 5.5]
Perpendicular Bisector equation: 4x-y-22.5 = 0
Vector OA = (5; 6) ; |OA| = 7.8102
Vector OB = (9; 5) ; |OB| = 10.2956
Scalar product OA .OB = 75
Angle ∠ AOB = 21°8'23″ = 0.369 rad