Line slope calculator 8x+5y=80


Enter coordinates of two different points:

Straight line given by points A[5; 8] and B[10; 0]

Calculation:

Slope-intercept form of line: y = -1.6x+16

Canonical form of the line equation: 8x+5y-80 = 0

Parametric form of the line equation:
x = 5t+5
y = -8t+8      ; t ∈ R

Slope: m = -1.6

Slope angle of line: φ = -57°59'41″ = -1.0122 rad

X intercept: x0 = 10

Y intercept: y0 = q = 16

Distance line from the origin: d0 = 8.48

The length of the segment AB: |AB| = 9.434

Vector: AB = (5; -8)

Normal vector: n = (8; 5)

Midpoint of the segment AB: M = [7.5; 4]

Perpendicular Bisector equation: 5x-8y-5.5 = 0


Vector OA = (5; 8) ;   |OA| = 9.434
Vector OB = (10; 0) ;   |OB| = 10
Scalar product OA .OB = 50
Angle ∠ AOB = 57°59'41″ = 1.0122 rad