Line slope calculator 8x+5y=80
Straight line given by points A[5; 8] and B[10; 0]
Calculation:
Slope: m = -1.6Slope-intercept form of line: y = -1.6x+16
Canonical form of the line equation: 8x+5y-80 = 0
Parametric form of the line equation:
x = 5t+5
y = -8t+8 ; t ∈ R
Slope angle of line: φ = -57°59'41″ = -1.0122 rad
X intercept: x0 = 10
Y intercept: y0 = q = 16
Distance line from the origin: d0 = 8.48
The length of the segment AB: |AB| = 9.434
Vector: AB = (5; -8)
Normal vector: n = (8; 5)
Midpoint of the segment AB: M = [7.5; 4]
Perpendicular Bisector equation: 5x-8y-5.5 = 0
Vector OA = (5; 8) ; |OA| = 9.434
Vector OB = (10; 0) ; |OB| = 10
Scalar product OA .OB = 50
Angle ∠ AOB = 57°59'41″ = 1.0122 rad