Line slope calculator 3x+5y=55


Enter coordinates of two different points:

Straight line given by points A[5; 8] and B[10; 5]

Calculation:

Slope-intercept form of line: y = -0.6x+11

Canonical form of the line equation: 3x+5y-55 = 0

Parametric form of the line equation:
x = 5t+5
y = -3t+8      ; t ∈ R

Slope: m = -0.6

Slope angle of line: φ = -30°57'50″ = -0.5404 rad

X intercept: x0 = 18.3333

Y intercept: y0 = q = 11

Distance line from the origin: d0 = 9.4324

The length of the segment AB: |AB| = 5.831

Vector: AB = (5; -3)

Normal vector: n = (3; 5)

Midpoint of the segment AB: M = [7.5; 6.5]

Perpendicular Bisector equation: 5x-3y-18 = 0


Vector OA = (5; 8) ;   |OA| = 9.434
Vector OB = (10; 5) ;   |OB| = 11.1803
Scalar product OA .OB = 90
Angle ∠ AOB = 31°25'46″ = 0.5485 rad