Line slope calculator 4x+y=28
Straight line given by points A[5; 8] and B[6; 4]
Calculation:
Slope: m = -4Slope-intercept form of line: y = -4x+28
Canonical form of the line equation: 4x+y-28 = 0
Parametric form of the line equation:
x = t+5
y = -4t+8 ; t ∈ R
Slope angle of line: φ = -75°57'50″ = -1.3258 rad
X intercept: x0 = 7
Y intercept: y0 = q = 28
Distance line from the origin: d0 = 6.791
The length of the segment AB: |AB| = 4.1231
Vector: AB = (1; -4)
Normal vector: n = (4; 1)
Midpoint of the segment AB: M = [5.5; 6]
Perpendicular Bisector equation: x-4y+18.5 = 0
Vector OA = (5; 8) ; |OA| = 9.434
Vector OB = (6; 4) ; |OB| = 7.2111
Scalar product OA .OB = 62
Angle ∠ AOB = 24°18'16″ = 0.4242 rad