Line slope calculator 5x+2y=41
Straight line given by points A[5; 8] and B[7; 3]
Calculation:
Slope: m = -2.5Slope-intercept form of line: y = -2.5x+20.5
Canonical form of the line equation: 5x+2y-41 = 0
Parametric form of the line equation:
x = 2t+5
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -68°11'55″ = -1.1903 rad
X intercept: x0 = 8.2
Y intercept: y0 = q = 20.5
Distance line from the origin: d0 = 7.6135
The length of the segment AB: |AB| = 5.3852
Vector: AB = (2; -5)
Normal vector: n = (5; 2)
Midpoint of the segment AB: M = [6; 5.5]
Perpendicular Bisector equation: 2x-5y+15.5 = 0
Vector OA = (5; 8) ; |OA| = 9.434
Vector OB = (7; 3) ; |OB| = 7.6158
Scalar product OA .OB = 59
Angle ∠ AOB = 34°47'46″ = 0.6073 rad