Line slope calculator 5x+3y=49


Enter coordinates of two different points:

Straight line given by points A[5; 8] and B[8; 3]

Calculation:

Slope-intercept form of line: y = -1.6667x+16.3333

Canonical form of the line equation: 5x+3y-49 = 0

Parametric form of the line equation:
x = 3t+5
y = -5t+8      ; t ∈ R

Slope: m = -1.6667

Slope angle of line: φ = -59°2'10″ = -1.0304 rad

X intercept: x0 = 9.8

Y intercept: y0 = q = 16.3333

Distance line from the origin: d0 = 8.4034

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; -5)

Normal vector: n = (5; 3)

Midpoint of the segment AB: M = [6.5; 5.5]

Perpendicular Bisector equation: 3x-5y+8 = 0


Vector OA = (5; 8) ;   |OA| = 9.434
Vector OB = (8; 3) ;   |OB| = 8.544
Scalar product OA .OB = 64
Angle ∠ AOB = 37°26'19″ = 0.6534 rad