Line slope calculator 5x+3y=49
Straight line given by points A[5; 8] and B[8; 3]
Calculation:
Slope: m = -1.6667Slope-intercept form of line: y = -1.6667x+16.3333
Canonical form of the line equation: 5x+3y-49 = 0
Parametric form of the line equation:
x = 3t+5
y = -5t+8 ; t ∈ R
Slope angle of line: φ = -59°2'10″ = -1.0304 rad
X intercept: x0 = 9.8
Y intercept: y0 = q = 16.3333
Distance line from the origin: d0 = 8.4034
The length of the segment AB: |AB| = 5.831
Vector: AB = (3; -5)
Normal vector: n = (5; 3)
Midpoint of the segment AB: M = [6.5; 5.5]
Perpendicular Bisector equation: 3x-5y+8 = 0
Vector OA = (5; 8) ; |OA| = 9.434
Vector OB = (8; 3) ; |OB| = 8.544
Scalar product OA .OB = 64
Angle ∠ AOB = 37°26'19″ = 0.6534 rad