Line slope calculator 3x-4y=18


Enter coordinates of two different points:

Straight line given by points A[6; 0] and B[10; 3]

Calculation:

Slope-intercept form of line: y = 0.75x-4.5

Canonical form of the line equation: 3x-4y-18 = 0

Parametric form of the line equation:
x = 4t+6
y = 3t      ; t ∈ R

Slope: m = 0.75

Slope angle of line: φ = 36°52'12″ = 0.6435 rad

X intercept: x0 = 6

Y intercept: y0 = q = -4.5

Distance line from the origin: d0 = 3.6

The length of the segment AB: |AB| = 5

Vector: AB = (4; 3)

Normal vector: n = (3; -4)

Midpoint of the segment AB: M = [8; 1.5]

Perpendicular Bisector equation: 4x+3y-36.5 = 0


Vector OA = (6; 0) ;   |OA| = 6
Vector OB = (10; 3) ;   |OB| = 10.4403
Scalar product OA .OB = 60
Angle ∠ AOB = 16°41'57″ = 0.2915 rad