Line slope calculator 3x-4y=18
Straight line given by points A[6; 0] and B[10; 3]
Calculation:
Slope: m = 0.75Slope-intercept form of line: y = 0.75x-4.5
Canonical form of the line equation: 3x-4y-18 = 0
Parametric form of the line equation:
x = 4t+6
y = 3t ; t ∈ R
Slope angle of line: φ = 36°52'12″ = 0.6435 rad
X intercept: x0 = 6
Y intercept: y0 = q = -4.5
Distance line from the origin: d0 = 3.6
The length of the segment AB: |AB| = 5
Vector: AB = (4; 3)
Normal vector: n = (3; -4)
Midpoint of the segment AB: M = [8; 1.5]
Perpendicular Bisector equation: 4x+3y-36.5 = 0
Vector OA = (6; 0) ; |OA| = 6
Vector OB = (10; 3) ; |OB| = 10.4403
Scalar product OA .OB = 60
Angle ∠ AOB = 16°41'57″ = 0.2915 rad