Line slope calculator 3x-4y=14
Straight line given by points A[6; 1] and B[10; 4]
Calculation:
Slope: m = 0.75Slope-intercept form of line: y = 0.75x-3.5
Canonical form of the line equation: 3x-4y-14 = 0
Parametric form of the line equation:
x = 4t+6
y = 3t+1 ; t ∈ R
Slope angle of line: φ = 36°52'12″ = 0.6435 rad
X intercept: x0 = 4.6667
Y intercept: y0 = q = -3.5
Distance line from the origin: d0 = 2.8
The length of the segment AB: |AB| = 5
Vector: AB = (4; 3)
Normal vector: n = (3; -4)
Midpoint of the segment AB: M = [8; 2.5]
Perpendicular Bisector equation: 4x+3y-39.5 = 0
Vector OA = (6; 1) ; |OA| = 6.0828
Vector OB = (10; 4) ; |OB| = 10.7703
Scalar product OA .OB = 64
Angle ∠ AOB = 12°20'21″ = 0.2154 rad