Line slope calculator 7x-4y=38


Enter coordinates of two different points:

Straight line given by points A[6; 1] and B[10; 8]

Calculation:

Slope-intercept form of line: y = 1.75x-9.5

Canonical form of the line equation: 7x-4y-38 = 0

Parametric form of the line equation:
x = 4t+6
y = 7t+1      ; t ∈ R

Slope: m = 1.75

Slope angle of line: φ = 60°15'18″ = 1.0517 rad

X intercept: x0 = 5.4286

Y intercept: y0 = q = -9.5

Distance line from the origin: d0 = 4.7133

The length of the segment AB: |AB| = 8.0623

Vector: AB = (4; 7)

Normal vector: n = (7; -4)

Midpoint of the segment AB: M = [8; 4.5]

Perpendicular Bisector equation: 4x+7y-63.5 = 0


Vector OA = (6; 1) ;   |OA| = 6.0828
Vector OB = (10; 8) ;   |OB| = 12.8062
Scalar product OA .OB = 68
Angle ∠ AOB = 29°11'51″ = 0.5096 rad