Line slope calculator 3x-2y=16


Enter coordinates of two different points:

Straight line given by points A[6; 1] and B[8; 4]

Calculation:

Slope-intercept form of line: y = 1.5x-8

Canonical form of the line equation: 3x-2y-16 = 0

Parametric form of the line equation:
x = 2t+6
y = 3t+1      ; t ∈ R

Slope: m = 1.5

Slope angle of line: φ = 56°18'36″ = 0.9828 rad

X intercept: x0 = 5.3333

Y intercept: y0 = q = -8

Distance line from the origin: d0 = 4.4376

The length of the segment AB: |AB| = 3.6056

Vector: AB = (2; 3)

Normal vector: n = (3; -2)

Midpoint of the segment AB: M = [7; 2.5]

Perpendicular Bisector equation: 2x+3y-21.5 = 0


Vector OA = (6; 1) ;   |OA| = 6.0828
Vector OB = (8; 4) ;   |OB| = 8.9443
Scalar product OA .OB = 52
Angle ∠ AOB = 17°6'10″ = 0.2985 rad