Line slope calculator 5x-3y=27


Enter coordinates of two different points:

Straight line given by points A[6; 1] and B[9; 6]

Calculation:

Slope-intercept form of line: y = 1.6667x-9

Canonical form of the line equation: 5x-3y-27 = 0

Parametric form of the line equation:
x = 3t+6
y = 5t+1      ; t ∈ R

Slope: m = 1.6667

Slope angle of line: φ = 59°2'10″ = 1.0304 rad

X intercept: x0 = 5.4

Y intercept: y0 = q = -9

Distance line from the origin: d0 = 4.6305

The length of the segment AB: |AB| = 5.831

Vector: AB = (3; 5)

Normal vector: n = (5; -3)

Midpoint of the segment AB: M = [7.5; 3.5]

Perpendicular Bisector equation: 3x+5y-40 = 0


Vector OA = (6; 1) ;   |OA| = 6.0828
Vector OB = (9; 6) ;   |OB| = 10.8167
Scalar product OA .OB = 60
Angle ∠ AOB = 24°13'40″ = 0.4229 rad