Line slope calculator 7x-3y=39


Enter coordinates of two different points:

Straight line given by points A[6; 1] and B[9; 8]

Calculation:

Slope-intercept form of line: y = 2.3333x-13

Canonical form of the line equation: 7x-3y-39 = 0

Parametric form of the line equation:
x = 3t+6
y = 7t+1      ; t ∈ R

Slope: m = 2.3333

Slope angle of line: φ = 66°48'5″ = 1.1659 rad

X intercept: x0 = 5.5714

Y intercept: y0 = q = -13

Distance line from the origin: d0 = 5.121

The length of the segment AB: |AB| = 7.6158

Vector: AB = (3; 7)

Normal vector: n = (7; -3)

Midpoint of the segment AB: M = [7.5; 4.5]

Perpendicular Bisector equation: 3x+7y-54 = 0


Vector OA = (6; 1) ;   |OA| = 6.0828
Vector OB = (9; 8) ;   |OB| = 12.0416
Scalar product OA .OB = 62
Angle ∠ AOB = 32°10'16″ = 0.5615 rad