Line slope calculator 2x+4y=52


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[10; 8]

Calculation:

Slope-intercept form of line: y = -0.5x+13

Canonical form of the line equation: 2x+4y-52 = 0

Parametric form of the line equation:
x = 4t+6
y = -2t+10      ; t ∈ R

Slope: m = -0.5

Slope angle of line: φ = -26°33'54″ = -0.4636 rad

X intercept: x0 = 26

Y intercept: y0 = q = 13

Distance line from the origin: d0 = 11.6276

The length of the segment AB: |AB| = 4.4721

Vector: AB = (4; -2)

Normal vector: n = (2; 4)

Midpoint of the segment AB: M = [8; 9]

Perpendicular Bisector equation: 4x-2y-14 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (10; 8) ;   |OB| = 12.8062
Scalar product OA .OB = 140
Angle ∠ AOB = 20°22'35″ = 0.3556 rad