Line slope calculator 2x+4y=52
Straight line given by points A[6; 10] and B[10; 8]
Calculation:
Slope: m = -0.5Slope-intercept form of line: y = -0.5x+13
Canonical form of the line equation: 2x+4y-52 = 0
Parametric form of the line equation:
x = 4t+6
y = -2t+10 ; t ∈ R
Slope angle of line: φ = -26°33'54″ = -0.4636 rad
X intercept: x0 = 26
Y intercept: y0 = q = 13
Distance line from the origin: d0 = 11.6276
The length of the segment AB: |AB| = 4.4721
Vector: AB = (4; -2)
Normal vector: n = (2; 4)
Midpoint of the segment AB: M = [8; 9]
Perpendicular Bisector equation: 4x-2y-14 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (10; 8) ; |OB| = 12.8062
Scalar product OA .OB = 140
Angle ∠ AOB = 20°22'35″ = 0.3556 rad