Line slope calculator 7x+y=52


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[7; 3]

Calculation:

Slope-intercept form of line: y = -7x+52

Canonical form of the line equation: 7x+y-52 = 0

Parametric form of the line equation:
x = t+6
y = -7t+10      ; t ∈ R

Slope: m = -7

Slope angle of line: φ = -81°52'12″ = -1.4289 rad

X intercept: x0 = 7.4286

Y intercept: y0 = q = 52

Distance line from the origin: d0 = 7.3539

The length of the segment AB: |AB| = 7.0711

Vector: AB = (1; -7)

Normal vector: n = (7; 1)

Midpoint of the segment AB: M = [6.5; 6.5]

Perpendicular Bisector equation: x-7y+39 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (7; 3) ;   |OB| = 7.6158
Scalar product OA .OB = 72
Angle ∠ AOB = 35°50'16″ = 0.6255 rad