Line slope calculator 5x+y=40


Enter coordinates of two different points:

Straight line given by points A[6; 10] and B[7; 5]

Calculation:

Slope-intercept form of line: y = -5x+40

Canonical form of the line equation: 5x+y-40 = 0

Parametric form of the line equation:
x = t+6
y = -5t+10      ; t ∈ R

Slope: m = -5

Slope angle of line: φ = -78°41'24″ = -1.3734 rad

X intercept: x0 = 8

Y intercept: y0 = q = 40

Distance line from the origin: d0 = 7.8446

The length of the segment AB: |AB| = 5.099

Vector: AB = (1; -5)

Normal vector: n = (5; 1)

Midpoint of the segment AB: M = [6.5; 7.5]

Perpendicular Bisector equation: x-5y+31 = 0


Vector OA = (6; 10) ;   |OA| = 11.6619
Vector OB = (7; 5) ;   |OB| = 8.6023
Scalar product OA .OB = 92
Angle ∠ AOB = 23°29'55″ = 0.4101 rad