Line slope calculator 5x+y=40
Straight line given by points A[6; 10] and B[7; 5]
Calculation:
Slope: m = -5Slope-intercept form of line: y = -5x+40
Canonical form of the line equation: 5x+y-40 = 0
Parametric form of the line equation:
x = t+6
y = -5t+10 ; t ∈ R
Slope angle of line: φ = -78°41'24″ = -1.3734 rad
X intercept: x0 = 8
Y intercept: y0 = q = 40
Distance line from the origin: d0 = 7.8446
The length of the segment AB: |AB| = 5.099
Vector: AB = (1; -5)
Normal vector: n = (5; 1)
Midpoint of the segment AB: M = [6.5; 7.5]
Perpendicular Bisector equation: x-5y+31 = 0
Vector OA = (6; 10) ; |OA| = 11.6619
Vector OB = (7; 5) ; |OB| = 8.6023
Scalar product OA .OB = 92
Angle ∠ AOB = 23°29'55″ = 0.4101 rad